**Question 01**

**A alone can complete a work in 16 days and B alone in 12 days. Starting with A, they work on alternate days**. **The total work will be completed in**

A complete work in 16 days

A’s 1 day work = 1/16 units

B complete work in 12 days

B’s 1 day work = 1/12 units

As they are working on alternate days.

So, the 2 day’s work = 1/16 + 1/12 = 7/48 units

Thus, work done in 6 pairs = 6 × 7/48 = 42/48 units=> **7/8 units** ( 12 days taken)

Thus, Remaining work = 1 – 7/8 = 1/8

On 13^{th} day, it will be A’s turn.

1/16 work done by A in 1 day.

Then, remaining work = 1/8 – 1/16 = 1/16

On 14^{th} day, it will be B’s turn.

1/12 work done by B in 1 day.

1/16 work will be done in (12 × 1/16) = ¾ day

**Therefore, total number of days = 12 + 1 + ¾ = 13 days**

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