Questions on graph of linear relation in x, y


Here you will get collection of questions related to drawing graph of linear functions between x and y.

All the questions are provided with solution for your reference.

To practice the below questions, you need to buy graph paper from your nearby stationary shop.

(01) Draw the graph of below linear functions;

(a) y = 5

(b) 2x + 6 = 0

(c) x = 5

(d) 7y + 21 = 0

(e) 4x – 10 = 0

Solution

(a) y = 5

The expression tells that the value of variable y is constant value 5. It indirectly also says that there is no fixed value of x variable.

So we will get straight line parallel to x axis.

questions and solutions on coordinate geometry for grade 9

(b) 2x + 6 = 0

Solving the equation;

2x + 6 = 0

2x = -6

x = -3

The equation tells that the value of x is a constant number -3.

It indirectly also tells that value of y variable is not fixed.

So we get straight line graph parallel to y axis.

questions on drawing graph of linear expression between x and y

(c) x = 5

It tells that value of variable x has constant value 5

Graph of x = 5

(d) 7y + 21 = 0

Solving the equation;

7y = -21

y = -3

The equation tells that y has constant value -3.

Graph of y = -3

(e) 4x – 10 = 0

Solving the equation;

4x = 10

x = 2.5

Graph of 4x - 10 = 0

(02) Study the linear equation and plot the graph.

(a) 4x + 2y = 4

(b) 3x + 6 = y

(c) -5x + 12y = 0

(d) x + 2y = 3

(e) 9y + 6 = 3x


Solution
Note that all the given expressions are linear equation which are straight line.

To plot the graph, just identify the two points of the equation and then join them with straight line.


(a) 4x + 2y = 4

Put x = 0;

4 (0) + 2y = 4

2y = 4

y = 2

So the first point is (0, 2)


Now put y = 0;

4x + 2(0) = 4

4x = 4

x = 1

So the second point is (1, 0)

Locate the two points (0, 2) and (1, 0) on the graph and join them with straight line.

Graph of 4x + 2y = 4

(b) 3x + 6 = y

Put x = 0;

3(0) + 6 = y

y = 6

So we got the first point (0, 6)


Put y = 0;

3x + 6 = 0

x = -2

We got the second point (-2, 0).


Locate the point (-2, 0) and (0, 6) on the graph and join them with straight line.

Graph of 3x + 6 = y

(c) -5x + 12y = 0

Put x = 0 in the equation;

-5(0) + 12y = 0

y = 0

We got the first point (0, 0)


Now put x = 12 in the equation;

-5(12) + 12y = 0

-60 + 12y = 0

12y = 60

y = 5

We got the second point (12, 5).

Locate two points (0, 0), (12, 5) on the graph and join them with straight line.

Graph of -5x + 12y = 0

(d) x + 2y = 3

Put x = 0 in the equation;

0 + 2y = 3

y = 1.5

We got first point (0, 1.5)


Now put x = 1 in the equation.

1 + 2y = 3

2y = 2

y = 1

We got second point (1, 1).


Locate the points (1, 1) and (0, 1.5) on graph and join them using straight line.

Graph of linear equation x + 2y = 3

(e) 9y + 6 = 3x

Put x = 2 in the main equation;

9y + 6 = 3 (2)

9y = 0

y = 0

We got the first point (2, 0).


Put y = 2 in the main equation.

9(2) + 6 = 3x

18 + 6 = 3x

24 = 3x

x = 8

we got second point (8, 2).


Locate two points (2, 0) and (8,2) on graph and join them with straight line.

Graph of 9y +6 = 3x




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