**Question 01**

**A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in**

A finish the work in 24 days

A’s 1 day work is 1/24

Similarly B’s 1 day work =1/9

and C’s 1 day work =1/12

As said, B & C start working together so,**(B + C)’s 1 day work = 1/9 + 1/12 = 7/36**

Work done by B and C in 3 days = (3 × 7/36) = 7/12

Remaining work = ( 1 – 7/12) = 5/12

**Now, 1/24 work is done by A in 1 day. So, 5/12 work is done by A in ( 24 × 5/12) = 10 days**

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