Question 01
A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in
A finish the work in 24 days
A’s 1 day work is 1/24
Similarly B’s 1 day work =1/9
and C’s 1 day work =1/12
As said, B & C start working together so,
(B + C)’s 1 day work = 1/9 + 1/12 = 7/36
Work done by B and C in 3 days = (3 × 7/36) = 7/12
Remaining work = ( 1 – 7/12) = 5/12
Now, 1/24 work is done by A in 1 day. So, 5/12 work is done by A in ( 24 × 5/12) = 10 days
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