## Prove that diagonal of Rhombus are perpendicular

Given:Rhombus is basically a parallelogram with following properties; (a) All sides are equal.i.e. AB = BC = CD = DA (b) Opposite sides are parallel. (c) Diagonals bisect each other.i.e. OA = OC and OD = OB To Prove:Prove that diagonals intersect at right angles.i.e. ∠AOB = 90 degree Proof:Consider triangle AOD and COD; OA …

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